Course Name: Stats Primer, Section No: 2, Unit No: 12, Unit type: Document
here: "Thus, P(G) = ଵ
ଷ and P(G | F) = P(even outcome | outcome greater than 4) = ଶ
ଷ."
page 7
I feel it doesn't explain well enough, everything is perfect but that step is missing, for someone who doesn't have the statistics it can the a big trouble, it would be better to explain how to obtain the 2/3 step by step.
Hi Sebastian,
We’re finding the probability of event G, given that event F has occurred, which is P(G | F).
We will calculate the conditional probability as follows: P(G | F) = P(G∩F)/P(F)
Step 1: Calculate P(F)
We already know that event F, which is the probability of getting a number greater than or equal to 4, when a fair die is rolled is 3/6 or 1/2.
Step 2: Calculate P(G∩F)
P(G∩F), which is the probability of getting an even number that is greater than or equal to 4 is 2/6.
Step 3: Calculate P(G | F)
Therefore, P(G | F) = P(G∩F)/P(F) = (2/6)/(3/6) = 2/3
I hope this helps to clarify the steps. Thank you for your suggestion; the steps will be added to the document as well.
Thanks,
Bhavika
Thank you very much Bhavika Balani!
Just what I was looking for, really apprecciate your help!
have a good one!